What is the inverse of 3(x+4)^2-2 ?

The inverse of 3(x+4)^2-2 is sqrt((x+2)/3)-4,-sqrt((x+2)/3)-4

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inverse of 3(x+4)^2-2

inverse

3 (x + 4)^{2} - 2

\frac{x + 2}{3} - 4, - \frac{x + 2}{3} - 4

Solution steps

y = 3 (x + 4)^{2} - 2

Replace

x

with

y

x = 3 (y + 4)^{2} - 2

Solve for

y, x = 3 (y + 4)^{2} - 2

\frac{x + 2}{3} - 4, - \frac{x + 2}{3} - 4

g (x) = \frac{2}{4 - x}

sin (2 θ)

f (x) = 0. 9^{x}

2^{x + 1} - 3

What is the inverse of 3(x+4)^2-2 ?
The inverse of 3(x+4)^2-2 is sqrt((x+2)/3)-4,-sqrt((x+2)/3)-4