What is the inverse of f(x)=2log_{10}(x)-5 ?

The inverse of f(x)=2log_{10}(x)-5 is 10^{(x+5)/2}

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inverse of f(x)=2log_{10}(x)-5

inverse

f (x) = 2 lo g_{10} (x) - 5

1 0^{\frac{x + 5}{2}}

Solution steps

y = 2 lo g_{10} (x) - 5

Replace

x

with

y

x = 2 lo g_{10} (y) - 5

Solve for

y, x = 2 lo g_{10} (y) - 5

1 0^{\frac{x + 5}{2}}

f (x) = arcsin (\frac{1}{x ^{2} + 1})

f (x) = x^{2} + 1, x > 0

51900000

f (x) = \frac{2 ( x + 3 ) - 2}{3}

f (x) = 2 + ln (3 x + 4)

What is the inverse of f(x)=2log_{10}(x)-5 ?
The inverse of f(x)=2log_{10}(x)-5 is 10^{(x+5)/2}