What is the inflection f(x)=4x^3-6x^2+5x-5 ?

The inflection f(x)=4x^3-6x^2+5x-5 is (1/2 ,-7/2)

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inflection f(x)=4x^3-6x^2+5x-5

inflection points

f (x) = 4 x^{3} - 6 x^{2} + 5 x - 5

(\frac{1}{2}, - \frac{7}{2})

Solution steps

f^{''} (x) = 24 x - 12

Find intervals:

Concave Downward

: - \infty < x < \frac{1}{2},

Concave Upward

: \frac{1}{2} < x < \infty

Plug

x = \frac{1}{2}

into

4 x^{3} - 6 x^{2} + 5 x - 5 : - \frac{7}{2}

(\frac{1}{2}, - \frac{7}{2})

\frac{11}{( x + 2 ) ( x - 2 )}

y = \frac{9}{t}

y = \frac{x ^{2} + 1}{x + 1}

y = - \frac{1}{2} x^{2} + 4 x - 2

(2.8, 1.1), (- 3.4, 5.7)

What is the inflection f(x)=4x^3-6x^2+5x-5 ?
The inflection f(x)=4x^3-6x^2+5x-5 is (1/2 ,-7/2)