What is the inverse of f(x)=4(x-5)^2-1 ?

The inverse of f(x)=4(x-5)^2-1 is (sqrt(x+1))/2+5,-(sqrt(x+1))/2+5

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inverse of f(x)=4(x-5)^2-1

inverse

f (x) = 4 (x - 5)^{2} - 1

\frac{x + 1}{2} + 5, - \frac{x + 1}{2} + 5

Solution steps

y = 4 (x - 5)^{2} - 1

Replace

x

with

y

x = 4 (y - 5)^{2} - 1

Solve for

y, x = 4 (y - 5)^{2} - 1

\frac{x + 1}{2} + 5, - \frac{x + 1}{2} + 5

h (x) = x^{2} - 4

f (x) = \frac{1}{- x + 1} - 2

x - 1 + 2

f (x) = 3 - x + 5

What is the inverse of f(x)=4(x-5)^2-1 ?
The inverse of f(x)=4(x-5)^2-1 is (sqrt(x+1))/2+5,-(sqrt(x+1))/2+5