What is the inverse of f(x)=-(x-1)^2+3,x>= 1 ?

The inverse of f(x)=-(x-1)^2+3,x>= 1 is sqrt(-x+3)+1,-sqrt(-x+3)+1

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inverse of f(x)=-(x-1)^2+3,x>= 1

inverse

f (x) = - (x - 1)^{2} + 3, x \geq 1

- x + 3 + 1, - - x + 3 + 1

Solution steps

y = - (x - 1)^{2} + 3

Replace

x

with

y

x = - (y - 1)^{2} + 3

Solve for

y, x = - (y - 1)^{2} + 3

- x + 3 + 1, - - x + 3 + 1

2 lo g_{10} (x - 2)

f (x) = - x + 1 + 3

f (x) = \frac{1}{x + 1} - 3

f (x) = (x + 2)^{3} + 3

What is the inverse of f(x)=-(x-1)^2+3,x>= 1 ?
The inverse of f(x)=-(x-1)^2+3,x>= 1 is sqrt(-x+3)+1,-sqrt(-x+3)+1