What is the inverse of f(x)=2^{(x+1)}-3 ?

The inverse of f(x)=2^{(x+1)}-3 is (ln(x+3))/(ln(2))-1

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inverse of f(x)=2^{(x+1)}-3

inverse

f (x) = 2^{(x + 1)} - 3

\frac{ln ( x + 3 )}{ln ( 2 )} - 1

Solution steps

y = 2^{x + 1} - 3

Replace

x

with

y

x = 2^{y + 1} - 3

Solve for

y, x = 2^{y + 1} - 3

\frac{ln ( x + 3 )}{ln ( 2 )} - 1

f (x) = \frac{x ^{3} - 4}{x ^{3} - 5}

\frac{3 x}{x ^{2} - 1}

f (x) = 7 x + 5 y = 2

f (x) = \frac{3}{x - 8}

f (x) = 7 x + 3

What is the inverse of f(x)=2^{(x+1)}-3 ?
The inverse of f(x)=2^{(x+1)}-3 is (ln(x+3))/(ln(2))-1