What is the inverse of f(x)=(8x-2)/(x+2) ?

The inverse of f(x)=(8x-2)/(x+2) is (-2-2x)/(x-8)

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inverse of f(x)=(8x-2)/(x+2)

inverse

f (x) = \frac{8 x - 2}{x + 2}

\frac{- 2 - 2 x}{x - 8}

Solution steps

y = \frac{8 x - 2}{x + 2}

Replace

x

with

y

x = \frac{8 y - 2}{y + 2}

Solve for

y, x = \frac{8 y - 2}{y + 2}

\frac{- 2 - 2 x}{x - 8}

f (x) = \frac{1}{6} x - 2

\frac{4 x}{x + 3}

F

d

lo g_{10} (x^{2} + 1)

What is the inverse of f(x)=(8x-2)/(x+2) ?
The inverse of f(x)=(8x-2)/(x+2) is (-2-2x)/(x-8)