What is the inverse of f(x)= 1/2 x^2+2 ?

The inverse of f(x)= 1/2 x^2+2 is sqrt(2x-4),-sqrt(2x-4)

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inverse of f(x)= 1/2 x^2+2

inverse

f (x) = \frac{1}{2} x^{2} + 2

2 x - 4, - 2 x - 4

Solution steps

y = \frac{1}{2} x^{2} + 2

Replace

x

with

y

x = \frac{1}{2} y^{2} + 2

Solve for

y, x = \frac{1}{2} y^{2} + 2

2 x - 4, - 2 x - 4

f (x) = \frac{2 x + 3}{3 x - 7}

cos (0)

f (x) = ln (3 x - 8) - ln (x) + 2

f (x) = \frac{1}{9 - x - 3}

f (x) = \frac{5}{4} x - 2

What is the inverse of f(x)= 1/2 x^2+2 ?
The inverse of f(x)= 1/2 x^2+2 is sqrt(2x-4),-sqrt(2x-4)