What is the inverse of f(x)=4(\sqrt[3]{x}+10) ?

The inverse of f(x)=4(\sqrt[3]{x}+10) is (x^3}{64}-\frac{15x^2)/8+75x-1000

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inverse of f(x)=4(\sqrt[3]{x}+10)

inverse

\frac{x ^{3}}{64} - \frac{15 x ^{2}}{8} + 75 x - 1000

Solution steps

Replace

x

with

y

Solve for

\frac{x ^{3}}{64} - \frac{15 x ^{2}}{8} + 75 x - 1000

f (x) = lo g_{2} (2 x - 4)

- 2 x^{3}

f (x) = 4 - 4 x

f (x) = 2 (4)^{x}

\frac{3}{2}

What is the inverse of f(x)=4(\sqrt[3]{x}+10) ?
The inverse of f(x)=4(\sqrt[3]{x}+10) is (x^3}{64}-\frac{15x^2)/8+75x-1000