What is the inverse of h(x)=arcsin(sqrt(x)) ?

The inverse of h(x)=arcsin(sqrt(x)) is sin^2(x)

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inverse of h(x)=arcsin(sqrt(x))

inverse

h (x) = arcsin (x)

sin^{2} (x)

Solution steps

arcsin (a) = b \Rightarrow a = sin (b)

x = sin (y)

Solve for

x, x = sin (y)

sin^{2} (y)

Substitute

y = x

sin^{2} (x)

f (x) = 3 x + 7

f (x) = 3 x + 3

- \frac{4}{x}

y = \frac{1 + 2 x}{7 + x}

f (x) = - x^{2} + 8 x - 14

What is the inverse of h(x)=arcsin(sqrt(x)) ?
The inverse of h(x)=arcsin(sqrt(x)) is sin^2(x)