What is the inverse of f(x)=6x^2+17 ?

The inverse of f(x)=6x^2+17 is sqrt((x-17)/6),-sqrt((x-17)/6)

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inverse of f(x)=6x^2+17

inverse

f (x) = 6 x^{2} + 17

\frac{x - 17}{6}, - \frac{x - 17}{6}

Solution steps

y = 6 x^{2} + 17

Replace

x

with

y

x = 6 y^{2} + 17

Solve for

y, x = 6 y^{2} + 17

\frac{x - 17}{6}, - \frac{x - 17}{6}

f (x) = ln (5 x^{4} + 12)

g (x) = 2^{x}

f (x) = lo g_{3} (x)

f (x) = 6 - \frac{x}{2}

What is the inverse of f(x)=6x^2+17 ?
The inverse of f(x)=6x^2+17 is sqrt((x-17)/6),-sqrt((x-17)/6)