What is the inverse of f(x)=(x-5)^2-7 ?

The inverse of f(x)=(x-5)^2-7 is sqrt(x+7)+5,-sqrt(x+7)+5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(x-5)^2-7

inverse

f (x) = (x - 5)^{2} - 7

x + 7 + 5, - x + 7 + 5

Solution steps

y = (x - 5)^{2} - 7

Replace

x

with

y

x = (y - 5)^{2} - 7

Solve for

y, x = (y - 5)^{2} - 7

x + 7 + 5, - x + 7 + 5

f (x) = (- 2, - 3)

\frac{7}{6 + x}

f (x) = \frac{( arcsin ( 5 x ) ) ^{2}}{4}

f (x) = \frac{2}{x - 5}

f (x) = \frac{x - 8}{x - 3}

What is the inverse of f(x)=(x-5)^2-7 ?
The inverse of f(x)=(x-5)^2-7 is sqrt(x+7)+5,-sqrt(x+7)+5