What is the critical 2x^3-6x ?

The critical 2x^3-6x is x=-1,x=1

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critical 2x^3-6x

critical points

2 x^{3} - 6 x

x = - 1, x = 1

Solution steps

2 x^{3} - 6 x

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 1

Identify critical points not in

f (x)

domain

Domain of

2 x^{3} - 6 x : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 1

f (x) = \frac{5 x + 7}{4 x - 5}

x^{2} + 4

\frac{x}{( x + 1 ) ^{n}}

f (x) = 3 x^{3} + 5 x^{2}

f (x) = 5^{x - 3}