What is the inverse of f(x)=\sqrt[3]{x-3}-1 ?

The inverse of f(x)=\sqrt[3]{x-3}-1 is x^3+3x^2+3x+4

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inverse of f(x)=\sqrt[3]{x-3}-1

inverse

x^{3} + 3 x^{2} + 3 x + 4

Solution steps

Replace

x

with

y

Solve for

x^{3} + 3 x^{2} + 3 x + 4

y = \frac{2 x + 4}{x - 3}

f (x) = \frac{5}{3} x - 15

y = (x - 2)^{3} + 1

f (x) = (x - 11)^{3} - 12

h (n) = 2 (n + 2)^{5}

What is the inverse of f(x)=\sqrt[3]{x-3}-1 ?
The inverse of f(x)=\sqrt[3]{x-3}-1 is x^3+3x^2+3x+4