What is the inverse of f(x)=((1-x))/(1+x) ?

The inverse of f(x)=((1-x))/(1+x) is (1-x)/(x+1)

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inverse of f(x)=((1-x))/(1+x)

inverse

f (x) = \frac{( 1 - x )}{1 + x}

\frac{1 - x}{x + 1}

Solution steps

y = \frac{1 - x}{1 + x}

Replace

x

with

y

x = \frac{1 - y}{1 + y}

Solve for

y, x = \frac{1 - y}{1 + y}

\frac{1 - x}{x + 1}

y = 1 2^{x}

f (x) = \frac{1}{2} e^{x}

f (x) = \frac{( 2 x - 3 )}{( x + 1 )}

9 lo g_{9} (3 x)

y = \frac{1 + e ^{x}}{1 - e ^{x}}

What is the inverse of f(x)=((1-x))/(1+x) ?
The inverse of f(x)=((1-x))/(1+x) is (1-x)/(x+1)