What is the inverse of f(x)=ln(1-x^2) ?

The inverse of f(x)=ln(1-x^2) is sqrt(-e^x+1),-sqrt(-e^x+1)

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inverse of f(x)=ln(1-x^2)

inverse

f (x) = ln (1 - x^{2})

- e^{x} + 1, - - e^{x} + 1

Solution steps

y = ln (1 - x^{2})

Replace

x

with

y

x = ln (1 - y^{2})

Solve for

y, x = ln (1 - y^{2})

- e^{x} + 1, - - e^{x} + 1

f (x) = \frac{x - 2}{9}

\frac{x + 5}{x + 10}

f (x) = x^{2} - 10 x + 2

sin (- 1)

What is the inverse of f(x)=ln(1-x^2) ?
The inverse of f(x)=ln(1-x^2) is sqrt(-e^x+1),-sqrt(-e^x+1)