What is the inverse of f(x)= 1/(x^3)-5 ?

The inverse of f(x)= 1/(x^3)-5 is cube root of 1/(x+5)

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inverse of f(x)= 1/(x^3)-5

inverse

f (x) = \frac{1}{x ^{3}} - 5

Solution steps

y = \frac{1}{x ^{3}} - 5

Replace

x

with

y

x = \frac{1}{y ^{3}} - 5

Solve for

y, x = \frac{1}{y ^{3}} - 5

- 2 x + 1

f (x) = 12 - 3 x^{2}

f (x) = 15 x

f (x) = \frac{x + 9}{2 x}

f (x) = - \frac{1}{9} x - 4

What is the inverse of f(x)= 1/(x^3)-5 ?
The inverse of f(x)= 1/(x^3)-5 is cube root of 1/(x+5)