What is the inverse of f(x)=2sqrt(x-1)-8 ?

The inverse of f(x)=2sqrt(x-1)-8 is 4x+(x^2)/4+17

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inverse of f(x)=2sqrt(x-1)-8

inverse

f (x) = 2 x - 1 - 8

4 x + \frac{x ^{2}}{4} + 17

Solution steps

y = 2 x - 1 - 8

Replace

x

with

y

x = 2 y - 1 - 8

Solve for

y, x = 2 y - 1 - 8

4 x + \frac{x ^{2}}{4} + 17

f (x) = \frac{4 x}{x + 2}

f (x) = ln (\frac{x + 1}{x - 1})

f (x) = \frac{4 x}{x + 3}

f (x) = 9 + 10 x

3 x^{\frac{1}{2}}

What is the inverse of f(x)=2sqrt(x-1)-8 ?
The inverse of f(x)=2sqrt(x-1)-8 is 4x+(x^2)/4+17