What is the inverse of f(x)=-2x^2+2 ?

The inverse of f(x)=-2x^2+2 is sqrt(-(x-2)/2),-sqrt(-(x-2)/2)

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inverse of f(x)=-2x^2+2

inverse

f (x) = - 2 x^{2} + 2

- \frac{x - 2}{2}, - - \frac{x - 2}{2}

Solution steps

y = - 2 x^{2} + 2

Replace

x

with

y

x = - 2 y^{2} + 2

Solve for

y, x = - 2 y^{2} + 2

- \frac{x - 2}{2}, - - \frac{x - 2}{2}

9 x - 9

f (x) = \frac{5 + x}{5}

+ 2 x - 3

9 x + 3

y = 3 x^{2} - 9

What is the inverse of f(x)=-2x^2+2 ?
The inverse of f(x)=-2x^2+2 is sqrt(-(x-2)/2),-sqrt(-(x-2)/2)