What is the inverse of R(q)=ln(1+10q^2) ?

The inverse of R(q)=ln(1+10q^2) is sqrt((e^q-1)/(10)),-sqrt((e^q-1)/(10))

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inverse of R(q)=ln(1+10q^2)

inverse

R (q) = ln (1 + 10 q^{2})

\frac{e ^{q} - 1}{10}, - \frac{e ^{q} - 1}{10}

Solution steps

y = ln (1 + 10 q^{2})

Replace

q

with

y

q = ln (1 + 10 y^{2})

Solve for

y, q = ln (1 + 10 y^{2})

\frac{e ^{q} - 1}{10}, - \frac{e ^{q} - 1}{10}

f (x) = - x + 4 + 3

- 7 a + 5

\frac{1}{6 x}

x^{2} - 8 x + 15

What is the inverse of R(q)=ln(1+10q^2) ?
The inverse of R(q)=ln(1+10q^2) is sqrt((e^q-1)/(10)),-sqrt((e^q-1)/(10))