What is the domain of ln((x+1)/(x-1)) ?

The domain of ln((x+1)/(x-1)) is x 1

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domain of ln((x+1)/(x-1))

domain

ln (\frac{x + 1}{x - 1})

x < - 1 or x > 1

Interval Notation

(- \infty, - 1) \cup (1, \infty)

Solution steps

Find positive values for logs:

x < - 1 or x > 1

Find undefined (singularity) points:

x = 1

Combine real regions and undefined points for final function domain

x < - 1 or x > 1

f (x) = 25 x - 1300

f (x) = 12 - x

f (x) = \frac{x + 8}{x - 10}

f (x) = \frac{1}{2 x}

f (x) = - \frac{6}{x ^{2} + 3}

What is the domain of ln((x+1)/(x-1)) ?
The domain of ln((x+1)/(x-1)) is x<-1\lor x>1