What is the inverse of f(x)=sqrt(x^2+3)+1 ?

The inverse of f(x)=sqrt(x^2+3)+1 is sqrt(x^2-2x-2),-sqrt(x^2-2x-2)

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inverse of f(x)=sqrt(x^2+3)+1

inverse

f (x) = x^{2} + 3 + 1

x^{2} - 2 x - 2, - x^{2} - 2 x - 2

Solution steps

y = x^{2} + 3 + 1

Replace

x

with

y

x = y^{2} + 3 + 1

Solve for

y, x = y^{2} + 3 + 1

x^{2} - 2 x - 2, - x^{2} - 2 x - 2

\frac{x}{4 x + 1}

f (x) = x + 5 - 2

f (x) = (\frac{x - 2}{3})^{7} + 6

f (x) = - \frac{4}{5} x

\frac{x - 5}{3}

What is the inverse of f(x)=sqrt(x^2+3)+1 ?
The inverse of f(x)=sqrt(x^2+3)+1 is sqrt(x^2-2x-2),-sqrt(x^2-2x-2)