What is the inverse of f(x)=-3(x-1)^2+9,x<= 1 ?

The inverse of f(x)=-3(x-1)^2+9,x<= 1 is sqrt(-(x-9)/3)+1,-sqrt(-(x-9)/3)+1

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inverse of f(x)=-3(x-1)^2+9,x<= 1

inverse

f (x) = - 3 (x - 1)^{2} + 9, x \leq 1

- \frac{x - 9}{3} + 1, - - \frac{x - 9}{3} + 1

Solution steps

y = - 3 (x - 1)^{2} + 9

Replace

x

with

y

x = - 3 (y - 1)^{2} + 9

Solve for

y, x = - 3 (y - 1)^{2} + 9

- \frac{x - 9}{3} + 1, - - \frac{x - 9}{3} + 1

f (x) = 1 + 2 (1 - 2 x)

f (x) = 24 x + 32

\frac{x + 1}{x ^{2} + 1}

f (x) = 3^{2 x}

x^{2} + 2 x + 5

What is the inverse of f(x)=-3(x-1)^2+9,x<= 1 ?
The inverse of f(x)=-3(x-1)^2+9,x<= 1 is sqrt(-(x-9)/3)+1,-sqrt(-(x-9)/3)+1