What is the inverse of f(x)=log_{4}(x^2)+1 ?

The inverse of f(x)=log_{4}(x^2)+1 is sqrt(4^{x-1)},-sqrt(4^{x-1)}

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inverse of f(x)=log_{4}(x^2)+1

inverse

f (x) = lo g_{4} (x^{2}) + 1

4^{x - 1}, - 4^{x - 1}

Solution steps

y = lo g_{4} (x^{2}) + 1

Replace

x

with

y

x = lo g_{4} (y^{2}) + 1

Solve for

y, x = lo g_{4} (y^{2}) + 1

4^{x - 1}, - 4^{x - 1}

f (x) = \frac{3}{x - 2}

f (x) = lo g_{10} (x - 4) + 2

f (x) = 5 x + 3 - 2

f (x) = \frac{3}{x - 7}

What is the inverse of f(x)=log_{4}(x^2)+1 ?
The inverse of f(x)=log_{4}(x^2)+1 is sqrt(4^{x-1)},-sqrt(4^{x-1)}