What is the inverse of 3(x+5)^2-4 ?

The inverse of 3(x+5)^2-4 is sqrt((x+4)/3)-5,-sqrt((x+4)/3)-5

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inverse of 3(x+5)^2-4

inverse

3 (x + 5)^{2} - 4

\frac{x + 4}{3} - 5, - \frac{x + 4}{3} - 5

Solution steps

y = 3 (x + 5)^{2} - 4

Replace

x

with

y

x = 3 (y + 5)^{2} - 4

Solve for

y, x = 3 (y + 5)^{2} - 4

\frac{x + 4}{3} - 5, - \frac{x + 4}{3} - 5

f (x) = \frac{4 x - 1}{3}

\frac{2}{3} x + 2

5 x - 2

f (x) = \frac{- x + 2}{2}

f (x) = - 5 x + 6

What is the inverse of 3(x+5)^2-4 ?
The inverse of 3(x+5)^2-4 is sqrt((x+4)/3)-5,-sqrt((x+4)/3)-5