What is the inverse of f(x)=((x-3))/(2x+1) ?

The inverse of f(x)=((x-3))/(2x+1) is (-3-x)/(2x-1)

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inverse of f(x)=((x-3))/(2x+1)

inverse

f (x) = \frac{( x - 3 )}{2 x + 1}

\frac{- 3 - x}{2 x - 1}

Solution steps

y = \frac{x - 3}{2 x + 1}

Replace

x

with

y

x = \frac{y - 3}{2 y + 1}

Solve for

y, x = \frac{y - 3}{2 y + 1}

\frac{- 3 - x}{2 x - 1}

f (x) = (x - 5)^{3} + 8

\frac{5 - 3 ^{x}}{2}

f (x) = x^{2} + 24 x + 144

f (x) = 8 e^{3 x} - 5

f (x) = \frac{2 x + 3}{2}

What is the inverse of f(x)=((x-3))/(2x+1) ?
The inverse of f(x)=((x-3))/(2x+1) is (-3-x)/(2x-1)