What is the inverse of f(x)=2x^2+4x+12 ?

The inverse of f(x)=2x^2+4x+12 is (-4+sqrt(8x-80))/4 ,(-4-sqrt(8x-80))/4

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inverse of f(x)=2x^2+4x+12

inverse

f (x) = 2 x^{2} + 4 x + 12

\frac{- 4 + 8 x - 80}{4}, \frac{- 4 - 8 x - 80}{4}

Solution steps

y = 2 x^{2} + 4 x + 12

Replace

x

with

y

x = 2 y^{2} + 4 y + 12

Solve for

y, x = 2 y^{2} + 4 y + 12

\frac{- 4 + 8 x - 80}{4}, \frac{- 4 - 8 x - 80}{4}

f (x) = \frac{5}{7} x - 2

y = 4 arccos (x)

f (x) = 5 x^{7} + 3

\frac{x - 2}{x + 7}

\frac{d}{d} x - 4

What is the inverse of f(x)=2x^2+4x+12 ?
The inverse of f(x)=2x^2+4x+12 is (-4+sqrt(8x-80))/4 ,(-4-sqrt(8x-80))/4