What is the inverse of (2^x)/(1+2^x) ?

The inverse of (2^x)/(1+2^x) is (ln(-x/(x-1)))/(ln(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of (2^x)/(1+2^x)

inverse

\frac{2 ^{x}}{1 + 2 ^{x}}

\frac{ln ( - \frac{x}{x - 1} )}{ln ( 2 )}

Solution steps

y = \frac{2 ^{x}}{1 + 2 ^{x}}

Replace

x

with

y

x = \frac{2 ^{y}}{1 + 2 ^{y}}

Solve for

y, x = \frac{2 ^{y}}{1 + 2 ^{y}}

\frac{ln ( - \frac{x}{x - 1} )}{ln ( 2 )}

f (x) = 7 x + 10

f (x) = lo g_{5} (x) - 1

arcsin (0)

f (x) = 3 x - 7 - 15

What is the inverse of (2^x)/(1+2^x) ?
The inverse of (2^x)/(1+2^x) is (ln(-x/(x-1)))/(ln(2))