What is the inverse of f(x)=log_{10}(x/(1-x)) ?

The inverse of f(x)=log_{10}(x/(1-x)) is (10^x)/(10^x+1)

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inverse of f(x)=log_{10}(x/(1-x))

inverse

f (x) = lo g_{10} (\frac{x}{1 - x})

\frac{1 0 ^{x}}{1 0 ^{x} + 1}

Solution steps

y = lo g_{10} (\frac{x}{1 - x})

Replace

x

with

y

x = lo g_{10} (\frac{y}{1 - y})

Solve for

y, x = lo g_{10} (\frac{y}{1 - y})

\frac{1 0 ^{x}}{1 0 ^{x} + 1}

f (x) = - x + 3 - 1

\frac{1}{( s + 2 ) ^{3}}

\frac{5 x}{2 x - 3}

What is the inverse of f(x)=log_{10}(x/(1-x)) ?
The inverse of f(x)=log_{10}(x/(1-x)) is (10^x)/(10^x+1)