What is the inverse of f(x)=(x+1)^2+6 ?

The inverse of f(x)=(x+1)^2+6 is sqrt(x-6)-1,-sqrt(x-6)-1

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inverse of f(x)=(x+1)^2+6

inverse

f (x) = (x + 1)^{2} + 6

x - 6 - 1, - x - 6 - 1

Solution steps

y = (x + 1)^{2} + 6

Replace

x

with

y

x = (y + 1)^{2} + 6

Solve for

y, x = (y + 1)^{2} + 6

x - 6 - 1, - x - 6 - 1

3 x - 2 + 4

f (x) = 600 (1 - x)^{2}

f (x) = 2 ln (\frac{( x + 5 )}{3})

1 - 2 - 3 x

x^{2} - 6 x + 10

What is the inverse of f(x)=(x+1)^2+6 ?
The inverse of f(x)=(x+1)^2+6 is sqrt(x-6)-1,-sqrt(x-6)-1