What is the critical (x^2-2x-2)/(x-3) ?

The critical (x^2-2x-2)/(x-3) is x=2,x=4

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critical (x^2-2x-2)/(x-3)

critical points

\frac{x ^{2} - 2 x - 2}{x - 3}

x = 2, x = 4

Solution steps

\frac{x ^{2} - 2 x - 2}{x - 3}

Find where

f^{'} (x)

is equal to zero or undefined

x = 2, x = 4, x = 3

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 2 x - 2}{x - 3} : x < 3 or x > 3

\frac{x ^{2} - 2 x - 2}{x - 3}

is not defined at

x = 3

, therefore:

x = 2, x = 4

x^{2} - 2 x + 4

f (x) = \frac{5 - x}{x ^{2} - 4 x}

9 x + 8 y = 5

- 4 x^{2} + 12

f (x) = \frac{x + 7}{x ^{2} - 16}

What is the critical (x^2-2x-2)/(x-3) ?
The critical (x^2-2x-2)/(x-3) is x=2,x=4