What is the inverse of f(x)=(x-20)^2,[20,infinity ] ?

The inverse of f(x)=(x-20)^2,[20,infinity ] is sqrt(x)+20,-sqrt(x)+20

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inverse of f(x)=(x-20)^2,[20,infinity ]

inverse

f (x) = (x - 20)^{2}, [20, \infty]

x + 20, - x + 20

Solution steps

y = (x - 20)^{2}

Replace

x

with

y

x = (y - 20)^{2}

Solve for

y, x = (y - 20)^{2}

x + 20, - x + 20

f (x) = \frac{10}{x} + 2

y = \frac{1}{3} lo g_{10} (3 x)

f (x) = \frac{10 x - 8}{3 x + 1}

- 4 x

\frac{9 x}{x ^{2} - 1}

What is the inverse of f(x)=(x-20)^2,[20,infinity ] ?
The inverse of f(x)=(x-20)^2,[20,infinity ] is sqrt(x)+20,-sqrt(x)+20