What is the inverse of sqrt((x+1)/(x-2)) ?

The inverse of sqrt((x+1)/(x-2)) is (1+2x^2)/(x^2-1)

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inverse of sqrt((x+1)/(x-2))

inverse

\frac{x + 1}{x - 2}

\frac{1 + 2 x ^{2}}{x ^{2} - 1}

Solution steps

y = \frac{x + 1}{x - 2}

Replace

x

with

y

x = \frac{y + 1}{y - 2}

Solve for

y, x = \frac{y + 1}{y - 2}

\frac{1 + 2 x ^{2}}{x ^{2} - 1}

f (x) = \frac{8}{4 - 2 x}

f (x) = \frac{x}{2} + \frac{1}{5}

f (x) = 100 (2)^{\frac{t}{3}}

f (x) = - x - 5

g (x) = - 3 x + 14

What is the inverse of sqrt((x+1)/(x-2)) ?
The inverse of sqrt((x+1)/(x-2)) is (1+2x^2)/(x^2-1)