What is the inverse of y= 5/(3(x+2))-8 ?

The inverse of y= 5/(3(x+2))-8 is (-6x-43)/(3(8+x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of y= 5/(3(x+2))-8

inverse

y = \frac{5}{3 ( x + 2 )} - 8

\frac{- 6 x - 43}{3 ( 8 + x )}

Solution steps

y = \frac{5}{3 ( x + 2 )} - 8

Replace

x

with

y

x = \frac{5}{3 ( y + 2 )} - 8

Solve for

y, x = \frac{5}{3 ( y + 2 )} - 8

\frac{- 6 x - 43}{3 ( 8 + x )}

f (x) = e^{- \frac{x ^{2}}{2}}

f (x) = 9 x^{2} - 3

f (x) = e^{2 x} + 5

f (x) = - 7 cos (2 x), 0 \leq x \leq \frac{π}{2}

lo g_{\frac{5}{4}} (5 x - 4 x^{2})

What is the inverse of y= 5/(3(x+2))-8 ?
The inverse of y= 5/(3(x+2))-8 is (-6x-43)/(3(8+x))