What is the inverse of f(x)=2x^2-8x+5 ?

The inverse of f(x)=2x^2-8x+5 is (8+sqrt(8x+24))/4 ,(8-sqrt(8x+24))/4

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inverse of f(x)=2x^2-8x+5

inverse

f (x) = 2 x^{2} - 8 x + 5

\frac{8 + 8 x + 24}{4}, \frac{8 - 8 x + 24}{4}

Solution steps

y = 2 x^{2} - 8 x + 5

Replace

x

with

y

x = 2 y^{2} - 8 y + 5

Solve for

y, x = 2 y^{2} - 8 y + 5

\frac{8 + 8 x + 24}{4}, \frac{8 - 8 x + 24}{4}

f (x) = 2 + 6 + 7 x

h (x) = \frac{x + 1}{x - 2}

f (x) = \frac{5 x}{x + 4}

f (x) = \frac{x + 2}{3 x - 1}

f (x) = 3 x - 1, - 1 \leq x < 5

What is the inverse of f(x)=2x^2-8x+5 ?
The inverse of f(x)=2x^2-8x+5 is (8+sqrt(8x+24))/4 ,(8-sqrt(8x+24))/4