What is the inverse of f(x)=(x-7)^2-3 ?

The inverse of f(x)=(x-7)^2-3 is sqrt(x+3)+7,-sqrt(x+3)+7

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inverse of f(x)=(x-7)^2-3

inverse

f (x) = (x - 7)^{2} - 3

x + 3 + 7, - x + 3 + 7

Solution steps

y = (x - 7)^{2} - 3

Replace

x

with

y

x = (y - 7)^{2} - 3

Solve for

y, x = (y - 7)^{2} - 3

x + 3 + 7, - x + 3 + 7

f (x) = \frac{1}{2} x - \frac{1}{4}

f (x) = 12 x - 2 x^{2}

3 - x + 4

h (x) = 3 x + 10

f (x) = \frac{x + 5}{8}

What is the inverse of f(x)=(x-7)^2-3 ?
The inverse of f(x)=(x-7)^2-3 is sqrt(x+3)+7,-sqrt(x+3)+7