What is the inverse of f(x)=2x^2+13 ?

The inverse of f(x)=2x^2+13 is sqrt((x-13)/2),-sqrt((x-13)/2)

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inverse of f(x)=2x^2+13

inverse

f (x) = 2 x^{2} + 13

\frac{x - 13}{2}, - \frac{x - 13}{2}

Solution steps

y = 2 x^{2} + 13

Replace

x

with

y

x = 2 y^{2} + 13

Solve for

y, x = 2 y^{2} + 13

\frac{x - 13}{2}, - \frac{x - 13}{2}

f (x) = (x + 18)^{3}

f (x) = \frac{3 x}{x ^{2} - 1}

- \frac{3}{5} x - 4

f (x) = \frac{1}{2 x ^{2} + 2}

f (x) = (5, - 2)

What is the inverse of f(x)=2x^2+13 ?
The inverse of f(x)=2x^2+13 is sqrt((x-13)/2),-sqrt((x-13)/2)