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Popular >

extreme f(x)=x^2+7x-4

Solution

extreme points

f (x) = x^{2} + 7 x - 4

Solution

Minimum (- \frac{7}{2}, - \frac{65}{4})

Solution steps

f^{'} (x) = 2 x + 7

Find intervals:

Decreasing

: - \infty < x < - \frac{7}{2},

Increasing

: - \frac{7}{2} < x < \infty

Plug

x = - \frac{7}{2}

into

x^{2} + 7 x - 4 : - \frac{65}{4}

Minimum (- \frac{7}{2}, - \frac{65}{4})

Popular Examples

domain of f(x)= 1/(x^2-2x-8)domain

f (x) = \frac{1}{x ^{2} - 2 x - 8}

inverse of f(x)=log_{2}(x+3)inverse

f (x) = lo g_{2} (x + 3)

asymptotes of f(x)=(3x-15)/(-x^2+25)asymptotes

f (x) = \frac{3 x - 15}{- x ^{2} + 25}

domain of 7/(x-1)domain

\frac{7}{x - 1}

inverse of f(x)=7^x inverse

f (x) = 7^{x}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+7x-4 ?
The extreme f(x)=x^2+7x-4 is Minimum(-7/2 ,-65/4)