What is the inverse of f(x)=\sqrt[3]{x-3}+1 ?

The inverse of f(x)=\sqrt[3]{x-3}+1 is x^3-3x^2+3x+2

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inverse of f(x)=\sqrt[3]{x-3}+1

inverse

x^{3} - 3 x^{2} + 3 x + 2

Solution steps

Replace

x

with

y

Solve for

x^{3} - 3 x^{2} + 3 x + 2

f (x) = \frac{( 1 - x )}{( 1 + x )}

f (x) = \frac{- 6 x - 3}{- 10 x + 8}

1 - e^{- 2 x}

f (x) = \frac{3 x}{8 x - 1}

9 - 3 x

What is the inverse of f(x)=\sqrt[3]{x-3}+1 ?
The inverse of f(x)=\sqrt[3]{x-3}+1 is x^3-3x^2+3x+2