What is the inverse of f(x)=2y-y^2 ?

The inverse of f(x)=2y-y^2 is 1-sqrt(-y+1),sqrt(-y+1)+1

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inverse of f(x)=2y-y^2

inverse

f (x) = 2 y - y^{2}

1 - - y + 1, - y + 1 + 1

Solution steps

x = 2 y - y^{2}

Replace

y

with

x

y = 2 x - x^{2}

Solve for

x, y = 2 x - x^{2}

1 - - y + 1, - y + 1 + 1

f (x) = x^{2} + 7, x \geq 0

f (x) = \frac{x - 5}{x - 3}

\frac{x - 7}{x + 5}

f (x) = \frac{7}{x - 5}

What is the inverse of f(x)=2y-y^2 ?
The inverse of f(x)=2y-y^2 is 1-sqrt(-y+1),sqrt(-y+1)+1