What is the inverse of f(x)=tan^2(x) ?

The inverse of f(x)=tan^2(x) is arctan(sqrt(x)),arctan(-sqrt(x))

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inverse of f(x)=tan^2(x)

inverse

f (x) = tan^{2} (x)

arctan (x), arctan (- x)

Solution steps

Solve for

tan (x), y = tan^{2} (x)

tan (x) = y, tan (x) = - y

tan (a) = b \Rightarrow a = arctan (b)

arctan (y), arctan (- y)

Substitute

y = x

arctan (x), arctan (- x)

\frac{1}{6 x + 7}

- x + 5

f (x) = \frac{( x + 2 )}{7}

\frac{5}{4 + x}

f (x) = \frac{2 x + 1}{1 - x}

What is the inverse of f(x)=tan^2(x) ?
The inverse of f(x)=tan^2(x) is arctan(sqrt(x)),arctan(-sqrt(x))