What is the inverse of f(x)=(2x-1)/(2x+1) ?

The inverse of f(x)=(2x-1)/(2x+1) is (-1-x)/(2(-1+x))

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inverse of f(x)=(2x-1)/(2x+1)

inverse

f (x) = \frac{2 x - 1}{2 x + 1}

\frac{- 1 - x}{2 ( - 1 + x )}

Solution steps

y = \frac{2 x - 1}{2 x + 1}

Replace

x

with

y

x = \frac{2 y - 1}{2 y + 1}

Solve for

y, x = \frac{2 y - 1}{2 y + 1}

\frac{- 1 - x}{2 ( - 1 + x )}

arccos (- \frac{1}{2})

f (x) = \frac{1}{e ^{x + 3}}

f (x) = (3)^{(9)^{x}}

f (x) = \frac{8}{x + 3}

What is the inverse of f(x)=(2x-1)/(2x+1) ?
The inverse of f(x)=(2x-1)/(2x+1) is (-1-x)/(2(-1+x))