What is the inverse of (1+x)/(sqrt(x-1)) ?

The inverse of (1+x)/(sqrt(x-1)) is (-2+x^2+xsqrt(x^2-8))/2 ,(-2+x^2-xsqrt(x^2-8))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of (1+x)/(sqrt(x-1))

inverse

\frac{1 + x}{x - 1}

\frac{- 2 + x ^{2} + x x ^{2} - 8}{2}, \frac{- 2 + x ^{2} - x x ^{2} - 8}{2}

Solution steps

y = \frac{1 + x}{x - 1}

Replace

x

with

y

x = \frac{1 + y}{y - 1}

Solve for

y, x = \frac{1 + y}{y - 1}

\frac{- 2 + x ^{2} + x x ^{2} - 8}{2}, \frac{- 2 + x ^{2} - x x ^{2} - 8}{2}

f (x) = \frac{3 x + 2}{x + 2}

f (x) = \frac{- 2 - 2 x}{x}

f (x) = \frac{2 x + 12}{3 x - 11}

f (x) = \frac{1}{( 3 x - 5 )}

lo g_{10} (4 x)

What is the inverse of (1+x)/(sqrt(x-1)) ?
The inverse of (1+x)/(sqrt(x-1)) is (-2+x^2+xsqrt(x^2-8))/2 ,(-2+x^2-xsqrt(x^2-8))/2