What is the inverse of f(x)=((x+3))/(x+9) ?

The inverse of f(x)=((x+3))/(x+9) is (3-9x)/(x-1)

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inverse of f(x)=((x+3))/(x+9)

inverse

f (x) = \frac{( x + 3 )}{x + 9}

\frac{3 - 9 x}{x - 1}

Solution steps

y = \frac{x + 3}{x + 9}

Replace

x

with

y

x = \frac{y + 3}{y + 9}

Solve for

y, x = \frac{y + 3}{y + 9}

\frac{3 - 9 x}{x - 1}

\frac{- 4 - 3 x}{7 x - 5}

f (x) = x^{3} - 3 x^{2} + 2 x + 1

f (x) = - x^{2}

f (x) = \frac{x ^{2} + x - 2}{x ^{2} - 3 x - 4}

f (x) = \frac{x - 1}{( x + 1 ) ^{2}}

What is the inverse of f(x)=((x+3))/(x+9) ?
The inverse of f(x)=((x+3))/(x+9) is (3-9x)/(x-1)