What is the inverse of f(x)=(9x^2+12)/2 ?

The inverse of f(x)=(9x^2+12)/2 is (sqrt(2x-12))/3 ,-(sqrt(2x-12))/3

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inverse of f(x)=(9x^2+12)/2

inverse

f (x) = \frac{9 x ^{2} + 12}{2}

\frac{2 x - 12}{3}, - \frac{2 x - 12}{3}

Solution steps

y = \frac{9 x ^{2} + 12}{2}

Replace

x

with

y

x = \frac{9 y ^{2} + 12}{2}

Solve for

y, x = \frac{9 y ^{2} + 12}{2}

\frac{2 x - 12}{3}, - \frac{2 x - 12}{3}

f (x) = lo g_{2} (5 x - 8)

f (x) = \frac{1}{2} (x - 3)^{2} + 1

- x^{2} + 16

2 x^{3} - 8

What is the inverse of f(x)=(9x^2+12)/2 ?
The inverse of f(x)=(9x^2+12)/2 is (sqrt(2x-12))/3 ,-(sqrt(2x-12))/3