What is the inverse of f(x)=((2x+1))/((x-3)) ?

The inverse of f(x)=((2x+1))/((x-3)) is (1+3x)/(x-2)

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inverse of f(x)=((2x+1))/((x-3))

inverse

f (x) = \frac{( 2 x + 1 )}{( x - 3 )}

\frac{1 + 3 x}{x - 2}

Solution steps

y = \frac{2 x + 1}{x - 3}

Replace

x

with

y

x = \frac{2 y + 1}{y - 3}

Solve for

y, x = \frac{2 y + 1}{y - 3}

\frac{1 + 3 x}{x - 2}

f (x) = \frac{( 2 x )}{( 3 x - 1 )}

f (x) = - \frac{5}{2} x + \frac{25}{2}

2 x^{3} + 9

- \frac{7}{8}

\frac{7 x + 6}{x - 5}

What is the inverse of f(x)=((2x+1))/((x-3)) ?
The inverse of f(x)=((2x+1))/((x-3)) is (1+3x)/(x-2)