What is the inverse of f(x)=(x-4)^2+7 ?

The inverse of f(x)=(x-4)^2+7 is sqrt(x-7)+4,-sqrt(x-7)+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(x-4)^2+7

inverse

f (x) = (x - 4)^{2} + 7

x - 7 + 4, - x - 7 + 4

Solution steps

y = (x - 4)^{2} + 7

Replace

x

with

y

x = (y - 4)^{2} + 7

Solve for

y, x = (y - 4)^{2} + 7

x - 7 + 4, - x - 7 + 4

3 sin (2 x)

f (x) = 4 x + 3

\frac{2 x + 3}{x - 3}

y = 3 + 2 x - x^{2}

f (x) = ln (x^{2} + 4)

What is the inverse of f(x)=(x-4)^2+7 ?
The inverse of f(x)=(x-4)^2+7 is sqrt(x-7)+4,-sqrt(x-7)+4