What is the inverse of f(x)=(\sqrt[3]{x-6})/2 ?

The inverse of f(x)=(\sqrt[3]{x-6})/2 is 8x^3+6

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inverse of f(x)=(\sqrt[3]{x-6})/2

inverse

8 x^{3} + 6

Solution steps

Replace

x

with

y

Solve for

8 x^{3} + 6

f (x) = 3 (t - 2)^{2} - 4

25 - x^{2}

f (x) = \frac{- 11 x + 6}{x + 6}

f (x) = 5 x^{2} - 4, x \geq 0

f (x) = 1 + \frac{4}{5} x

What is the inverse of f(x)=(\sqrt[3]{x-6})/2 ?
The inverse of f(x)=(\sqrt[3]{x-6})/2 is 8x^3+6