What is the inverse of f(x)=1-sqrt(1-x^2) ?

The inverse of f(x)=1-sqrt(1-x^2) is sqrt(-x^2+2x),-sqrt(-x^2+2x)

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inverse of f(x)=1-sqrt(1-x^2)

inverse

f (x) = 1 - 1 - x^{2}

- x^{2} + 2 x, - - x^{2} + 2 x

Solution steps

y = 1 - 1 - x^{2}

Replace

x

with

y

x = 1 - 1 - y^{2}

Solve for

y, x = 1 - 1 - y^{2}

- x^{2} + 2 x, - - x^{2} + 2 x

f (x) = - 5 x^{2} - 9

(x - 2)^{5} + 3

f (x) = - x^{2} + 4 x - 1

f (x) = \frac{x + 3}{x - 2}

\frac{2}{3} x + \frac{1}{2}

What is the inverse of f(x)=1-sqrt(1-x^2) ?
The inverse of f(x)=1-sqrt(1-x^2) is sqrt(-x^2+2x),-sqrt(-x^2+2x)