What is the inverse of f(x)=sqrt(10-x^2) ?

The inverse of f(x)=sqrt(10-x^2) is sqrt(-x^2+10),-sqrt(-x^2+10)

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inverse of f(x)=sqrt(10-x^2)

inverse

f (x) = 10 - x^{2}

- x^{2} + 10, - - x^{2} + 10

Solution steps

y = 10 - x^{2}

Replace

x

with

y

x = 10 - y^{2}

Solve for

y, x = 10 - y^{2}

- x^{2} + 10, - - x^{2} + 10

+ arcsin (x)

(2 (x + 9))^{3} - 4

f (x) = \frac{16}{25} x^{2}

21.4 + 3 n + 17

f (x) = \frac{4 x}{x - 5}

What is the inverse of f(x)=sqrt(10-x^2) ?
The inverse of f(x)=sqrt(10-x^2) is sqrt(-x^2+10),-sqrt(-x^2+10)